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1-2y-15y^2=0
a = -15; b = -2; c = +1;
Δ = b2-4ac
Δ = -22-4·(-15)·1
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-8}{2*-15}=\frac{-6}{-30} =1/5 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+8}{2*-15}=\frac{10}{-30} =-1/3 $
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